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IOS json 解析遇到錯誤問題解決辦法

編輯:IOS開發綜合

概要:

Error Domain=NSCocoaErrorDomain Code=3840 "The operation couldn't be completed. (Cocoa error 3840.)" (Unescaped control character around character 1419.) UserInfo=0x1563cdd0 {NSDebugDescription=Unescaped control character around character 1419.}

之前解析json的時候都是標准格式,json數據當中沒有 \n \r \t 等制表符。

今天在解析的時候發現json解析時好時壞,用在線json解析也米有問題。找了半天終於發現是制表符在作怪,由於標准的json解析是不允許有這幾個制表符的。所以在收到保溫的時候我們需要把這幾個制表符給過濾掉。

NSString * responseString = [request responseString];

responseString = [responseString stringByReplacingOccurrencesOfString:@"\r\n" withString:@""];

responseString = [responseString stringByReplacingOccurrencesOfString:@"\n" withString:@""];

responseString = [responseString stringByReplacingOccurrencesOfString:@"\t" withString:@""];

NSLog(@"responseString = %@",responseString);

SBJsonParser *parser = [[[SBJsonParser alloc]init] autorelease];

id returnObject = [parser objectWithString:responseString];

NSDictionary *userInfo = nil;

NSArray *userArr = nil;

if ([returnObject isKindOfClass:[NSDictionary class]]) {

if (userInfo) {

[userArr release];

}

userInfo = (NSDictionary*)returnObject;

}

else if ([returnObject isKindOfClass:[NSArray class]]) {

userArr = (NSArray*)returnObject;

}

NSError* e = nil;



//系統自帶的解析方式。

NSDictionary * userInfo = [NSJSONSerialization JSONObjectWithData:[jsonString dataUsingEncoding:NSUTF8StringEncoding] options:NSJSONReadingMutableLeaves error:&e];

if (e) {

NSLog(@"%@",e);

}

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