IOS json的解析可能會遇到錯誤問題，如何解決呢？摸不著頭腦的話不妨來看看這篇文章吧，解決方法介紹的很詳細。

概要：

Error Domain=NSCocoaErrorDomain Code=3840 "The operation couldn't be  completed. (Cocoa error 3840.)" (Unescaped control character around  character 1419.) UserInfo=0x1563cdd0 {NSDebugDescription=Unescaped  control character around character 1419.}

之前解析json的時候都是標准格式，json數據當中沒有 \n \r \t 等制表符。

今天在解析的時候發現json解析時好時壞，用在線json解析也米有問題。找了半天終於發現是制表符在作怪，由於標准的json解析是不允許有這幾個制表符的。所以在收到保溫的時候我們需要把這幾個制表符給過濾掉。

 

 代碼如下復制代碼

NSString * responseString = [request responseString];

 

responseString = [responseString stringByReplacingOccurrencesOfString:@"\r\n"withString:@""];

 

responseString = [responseString stringByReplacingOccurrencesOfString:@"\n"withString:@""];

 

responseString = [responseString stringByReplacingOccurrencesOfString:@"\t"withString:@""];

 

NSLog(@"responseString = %@",responseString);

 

SBJsonParser *parser = [[[SBJsonParser alloc]init] autorelease];

 

id returnObject = [parser objectWithString:responseString];

 

NSDictionary *userInfo = nil;

 

NSArray *userArr = nil;

 

if([returnObject isKindOfClass:[NSDictionaryclass]]) {

 

if(userInfo) {

 

[userArr release];

 

}

 

userInfo = (NSDictionary*)returnObject;

 

}

 

elseif([returnObject isKindOfClass:[NSArrayclass]]) {

 

userArr = (NSArray*)returnObject;

 

}

 

NSError* e = nil;

//系統自帶的解析方式。

NSDictionary * userInfo = [NSJSONSerialization JSONObjectWithData:[jsonString dataUsingEncoding:NSUTF8StringEncoding] options:NSJSONReadingMutableLeaves error:&e];

 

if(e) {

 

NSLog(@"%@",e);

 

}